Semiconductors Intro

EE

P-N

[2] Ch3

  • P stands for positive (+): Carries holes (misses \(e^-\))
  • N stands for negative (-): Carries \(e^-\)

Silicon has 4 valence \(e^-\), and is the typical semiconductor base. It is doped with:

  • Boron, owns 3 valence \(e^-\), lacks a \(e^-\): P type (anode)
  • Phosphorous, owns 5 valence \(e^-\), donates one: N type (cathode)

Put P and N together: Diode (aka PN junction)

Diodes, simplified

Let the diode have a fixed voltage drop \(v_D\) (also known as cut-in voltage \(v_{\gamma}\)).

If \((V_{in} > v_D) :\ V_{out} = V_{in} - v_D\) -> Behaves like a resistor

Else: \(i_D = 0\) -> Open circuit

Standard values: \(v_{\gamma} = 0.7\) for simple diodes, \(v_{\gamma} = 1.8V\) for red LEDs.

Zener Diodes

Normal diodes get damaged if a high reverse voltage is applied. A zener diode is designed to allow reverse current by operating at a special voltage \(V_Z\):

If \((V_{in} > v_D) :\ V_{out} = V_{in} - v_D\)

If \((V_{in} < -V_Z):\ V_{out} = V_Z\)

Else: \(i_D = 0\) -> Open circuit

\(V_Z\) is usually set to be much higher than \(v_{\gamma}\), over 6V.

AC to DC

Rectification:

  • Diode rectifier
  • Filter
  • Voltage regulator

Diode rectifier

Type 1: Four diodes in diamond

  • The current flows through 2 diodes
\[V_{out} = V_{in} - 2v_{\gamma}\]

Type 2: Two diodes at each end

  • The current flows through 1 diode
  • The receiving winding is center-tapped to ground, in parallel to load
\[V_{out} = V_{in} - v_{\gamma}\]

Filter

A capacitor between \(V_{out}\) and ground, parallel to the load.

It creates ripple voltage:

\[V_r = \frac{V_M}{2fRC}\]

Where \(V_M\) is the maximum voltage at \(V_{out}\).

Voltage Regulator

An ideal diode has a constant voltage. So we put one in parallel to our load to get DC.

The voltage drop for a normal diode \(v_{\gamma}\) is usually low. So we use a Zener diode in reverse bias to use the high voltage \(V_Z\).

A voltage regulator has a safe operating range (min and max \(V_Z\)). \(R_i\) helps protect the diode.

Let \(I_Z\) be the current through the diode.

\[I_Z(min) = \frac{V_{in}(min) - V_Z}{R_i} - I_L (max)\] \[I_Z(max) = \frac{V_{in}(max) - V_Z}{R_i} - I_L (min)\]

Example: let \(V_Z = 9\ V,\ V_{in} = (11, 13.6)\ V,\ I_{RL} (max) = 100\ mA.\) If \(I_Z (min) = 0.1 I_Z (max)\), what should be \(R_i\)?

Transformer overview


Other diode uses

Clipper circuit

Clip the input voltage to a limit

Let \(V_B\) be a constant DC volt source, with polarity against the diode.

The voltage between the diode and ground remains the same, since \(v_{\gamma}\) and \(V_B\) do not change.

Clamper circuit

Shift a DC voltage without changing its “shape”

Logic gates

See diode logic gates